• # question_answer A conical tent is of diameter 12m at the base and its height is 8m. Find the area of the canvas (in${{m}^{2}}$) required to make the tent. A)  188.57 m   B)  288 m          C)  400 m                         D)  500 m

(a): area of canvas $=\pi rl=n\pi \sqrt{{{r}^{2}}+{{h}^{2}}}$ $=\frac{22}{7}\times 6\times \sqrt{{{6}^{2}}+{{8}^{2}}}=\frac{22}{7}\times 6\times 10=188.57m.$