A) 13 : 11
B) 14 : 11
C) 15 : 11
D) 16 : 11
Correct Answer: B
Solution :
Let \[4x\] be the perimeter of the square, so that its area is \[{{x}^{2}}.\] Circumference\[=2\pi r=4x\] \[\therefore \] \[r=\frac{2x}{\pi }\] \[\therefore \] \[\text{Area}=\pi {{r}^{2}}=\pi {{\left( \frac{2x}{\pi } \right)}^{2}}=\pi \frac{4}{{{\pi }^{2}}}{{x}^{2}}\] \[\therefore \] Ratio of area of the circle and the square \[=\frac{4}{\pi }{{x}^{2}}:{{x}^{2}}\] \[=4:\pi \]or \[4:\frac{22}{7}\] \[=28:22\]or \[14:11\]
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