A) 100%
B) 200%
C) 300%
D) 400%
Correct Answer: C
Solution :
Let the initial length and width be \[l\] & b respectively. Then the initial area\[=l\times b\] According to the question, New length and width will be \[2l\] and \[2b\] respectively. \[\therefore \] New area\[=2l\times 2b=4lb\] Increment in area \[=\frac{4lb-lb}{lb}\times 100%=300%.\]
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