A) 1.5%
B) 3%
C) 4.5%
D) 5.7%
Correct Answer: B
Solution :
Let the initial side be a. The final side\[=a+a\times \frac{1.5}{100}=\frac{203}{200}a\] Initial area of the triangle\[=\frac{\sqrt{3}}{4}{{a}^{2}}\] Final area of the triangle\[=\frac{\sqrt{3}}{4}{{\left( \frac{203}{200}a \right)}^{2}}\] The percentage increase in area \[=\frac{\frac{\sqrt{3}}{4}{{\left( \frac{203}{200}a \right)}^{2}}-\frac{\sqrt{3}}{4}{{a}^{2}}}{\frac{\sqrt{3}}{4}{{a}^{2}}}\times 100%\] \[=\left[ {{\left( \frac{203}{200} \right)}^{2}}-1 \right]\times 100%=3.02%\simeq 3%\]
You need to login to perform this action.
You will be redirected in
3 sec
