A) \[\text{12 c}{{\text{m}}^{\text{2}}}\]
B) \[\text{15 c}{{\text{m}}^{\text{2}}}\]
C) \[\text{2}0\text{ c}{{\text{m}}^{\text{2}}}\]
D) \[\text{6 c}{{\text{m}}^{\text{2}}}\]
Correct Answer: D
Solution :
Area of the triangle \[=\sqrt{s(s-a)\,(s-b)\,(s-c)}\] \[s=\frac{3+4+5}{2}=6\] \[=\sqrt{6(6-3)(6-4)\,(6-5)}\] \[=\sqrt{6\times 3\times 2\times 1}=6\,c{{m}^{2}}\]
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