A) \[72\sqrt{3}\,\pi \,c{{m}^{3}}\]
B) \[71\sqrt{3}\,\pi \,c{{m}^{3}}\]
C) \[70\sqrt{2}\,\pi \,c{{m}^{3}}\]
D) \[69\sqrt{2}\,\pi \,c{{m}^{3}}\]
Correct Answer: A
Solution :
Diameter of base \[=\text{ }12\text{ }cm\] and height of cone \[=\sqrt{{{12}^{2}}-{{6}^{2}}}\] \[=6\sqrt{3}\,cm\] \[\therefore \] Volume of cone \[=\frac{1}{3}\pi \times radiu{{s}^{2}}\times height\] \[=\frac{1}{3}\pi \times {{6}^{2}}\times 6\sqrt{3}\] \[=72\sqrt{3}\,\pi \,c{{m}^{3}}\]
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