A) 2 times
B) 3 times
C) 4 times
D) 5 times
Correct Answer: C
Solution :
Let r and A be the radius and length of a wire. \[\therefore \] Volume of wire \[=\pi \,{{r}^{2}}h\] New radius of wire \[=\frac{r}{2}\] If h be the new length of the wire, then by hypothesis, \[\pi {{r}^{2}}h=\pi {{\left( \frac{r}{2} \right)}^{2}}h'=\frac{\pi {{r}^{2}}h}{4}\] \[\therefore \] \[h'=4h\] \[=4\] times h
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