A) \[\text{5196}{{\text{m}}^{\text{3}}}\]
B) \[\text{52}00{{\text{m}}^{\text{3}}}\]
C) \[\text{521}0\text{ }{{\text{m}}^{\text{3}}}\]
D) \[\text{522}0\text{ }{{\text{m}}^{\text{3}}}\]
Correct Answer: A
Solution :
Volume of pyramid\[=\frac{1}{3}\] [Area of hexagonal base of side \[10\,m\times \]Height] \[=\frac{1}{3}\left[ \frac{3\sqrt{3}}{4}\,{{(10)}^{2}}\times 60 \right]=5196\,{{m}^{3}}\]
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