A) \[51.33\,c{{m}^{2}}\]
B) \[102.7\,c{{m}^{2}}\]
C) \[205.34\,c{{m}^{2}}\]
D) \[108.6\,c{{m}^{2}}\]
Correct Answer: B
Solution :
Area of sector OBCO \[=\frac{{{30}^{o}}}{{{360}^{o}}}\times \pi \times 21\times 21\] \[=\frac{22}{7}\times \frac{7}{4}\times 21\] \[=\frac{231}{2}=115.5\,c{{m}^{2}}\] Area of sector OADO \[=\frac{{{30}^{o}}}{{{360}^{o}}}\times \pi \times 7\times 7\] \[=\frac{1}{12}\times \frac{22}{7}\times 7\times 7\] \[=\frac{77}{16}=12.8\,\,c{{m}^{2}}\] So, area of shaded region \[=115.5-12.8=102.7\,c{{m}^{2}}\]
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