A) Area
B) Circumference
C) 2n
D) 4
Correct Answer: D
Solution :
(d): \[C=2\pi r\] & \[A=\pi {{r}^{2}}\Rightarrow \] \[2\pi r=\pi {{r}^{2}}\Rightarrow 2r={{r}^{2}}\] \[\Rightarrow \,\,2=r\Rightarrow 4=2r=d,\]hence diameter = 4You need to login to perform this action.
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