• # question_answer The perimeter of two squares are 16 cm, 12 cm. The perimeter of a square whose area is equal to the sum of the areas of first two squares would be: A) $18\,\,cm$                              B) $\text{20}\,\,cm$C) $\text{28}\,\,cm$                   D) $\text{30}\,\,cm$

Side of 1st square $=4\,\,cm:$ Area $=16\,\,c{{m}^{2}}$ Side of 2nd square $=3\,\,cm:$ Area$=9\,\,c{{m}^{2}}$