question_answer

In the given figure (1), (2), (3) and (4) are squares. The perimeter of the square (1) and (2) are respectively 20 and 24 units. The area of the entire figure.

A)  471 sq. unit   

B)  747 sq. unit   

C)  417 sq. unit                

D)  472 sq. unit

Correct Answer: A

Solution :

Perimeter of '1'= 20 unit \[\therefore \]Side \[=\frac{20}{4}\equiv 5\] unit Perimeter of '2'= 24 unit \[\therefore \]  Side \[=\frac{24}{4}=6\] unit Area of entire figure \[=\left\{ {{\left( 5 \right)}^{2}}{{(6)}^{2}}+{{(11)}^{2}}+{{(17)}^{2}} \right\}\] \[=\{25+36+121+289\}=471\,\,sq.\]units