A) \[64\,\,c{{m}^{2}},\,\,32\,\,cm\]
B) \[\text{36}\,\,c{{m}^{2}},\,\,12\,\,cm\]
C) \[8\,\,c{{m}^{2}},\,\,5\,\,cm\]
D) \[9\,\,c{{m}^{2}},\,\,7\,\,cm\]
Correct Answer: A
Solution :
Area of 'A'\[=25\,\,c{{m}^{2}}\] \[\therefore \] Side \[=~5\,\,cm\] Perimeter of\[B=12\,\,cm\] \[\therefore \] Side \[=\frac{12}{4}=3\,\,cm\] \[\therefore \]Side of \[C=5+3=8\,\,cm\] \[\therefore \]Area \[={{(8\,\,cm)}^{2}}=64\,\,c{{m}^{2}}\] \[\therefore \]Perimeter\[=4\times 8\,\,cm=32\,\,cm\]
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