Answer:
Consider two rods of steel and rubber, each having length \[l\] and area of cross-section A. If they are subjected to the same deforming force F, then the extension \[\Delta {{l}_{S}}\]produced in the steel rod will be less than the extension \[\Delta {{l}_{r}}\] in the rubber rod, i.e., \[\Delta {{l}_{s}}<\Delta {{l}_{r}}\]. Now \[{{\Upsilon }_{s}}=\frac{F}{A}.\frac{l}{\Delta {{l}_{s}}}\] and \[{{\Upsilon }_{r}}=\frac{F}{A}.\frac{l}{\Delta {{l}_{r}}}\] \[\therefore \] \[\frac{{{\Upsilon }_{s}}}{{{\Upsilon }_{r}}}=\frac{\Delta {{l}_{r}}}{\Delta {{l}_{s}}}\] As \[\Delta {{l}_{s}}<\Delta {{l}_{r'}}\] so \[{{\Upsilon }_{s}}>{{\Upsilon }_{r}}\] i.e., Young's modulus for steel is greater than that of rubber. Hence steel is more elastic than rubber.
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