7th Class Mathematics Related to Competitive Exam Question Bank Mathematical Operations

  • question_answer
    If 3 + 5 = 16; 7 + 9 = 64; 10 + 12 = 121, then 11 + 3 =?

    A) 56                               

    B) 48

    C) 49                   

    D) 196

    Correct Answer: C

    Solution :

        The rule is \[a+b={{\left( \frac{a+b}{2} \right)}^{2}}\] \[3+5={{\left( \frac{3+5}{2} \right)}^{2}}\text{etc}\text{.}\] \[\therefore 11+3={{\left( \frac{11+3}{2} \right)}^{2}}=49\]     


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