JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank Mathematical induction and Divisibility problems

  • question_answer
    If n is a natural number then \[{{\left( \frac{n+1}{2} \right)}^{n}}\ge n\,!\] is true when

    A) n > 1

    B) n ³ 1

    C) n > 2

    D) n ³ 2

    Correct Answer: B

    Solution :

    Check through option, the condition \[{{\left( \frac{n+1}{2} \right)}^{n}}\ge n\,!\] is true for\[n\ge 1\].


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