A) n > 1
B) n
C) n > 2
D) None of these
Correct Answer: D
Solution :
\[=\sum\limits_{r=0}^{n}{{{(-1)}^{r}}{{\,}^{n}}{{C}_{r}}}.\frac{1}{{{2}^{r}}}+\sum\limits_{r=0}^{n}{{{(-1)}^{r}}}{{.}^{n}}{{C}_{r}}\frac{{{3}^{r}}}{{{2}^{2r}}}+\]. It is always odd (statement) but square of any odd number is always odd and also, sum of two odd number is always even. So for no any ?n? for which this statement is true.
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