JEE Main & Advanced Mathematics Binomial Theorem and Mathematical Induction Question Bank Mathematical induction and Divisibility problems

  • question_answer
    For all positive integral values of n, \[{{3}^{2n}}-2n+1\] is divisible by

    A) 2

    B) 4

    C) 8

    D) 12

    Correct Answer: A

    Solution :

    Putting \[n=2\] in \[{{3}^{2n}}-2n+1\] then, \[{{3}^{2\times 2}}-2\times 2+1=81-4+1=78\], which is divisible by 2.


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