A) \[x+y\]
B) \[x-y\]
C) \[{{x}^{2}}+{{y}^{2}}\]
D) \[{{x}^{2}}+xy\]
Correct Answer: A
Solution :
\[{{x}^{2n-1}}+{{y}^{2n-1}}\] is always contain equal odd power. So it is always divisible by\[x+y\].
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