A) 2
B) 3
C) 1
D) 0
Correct Answer: C
Solution :
(c): \[\frac{1}{2}{{\log }_{10}}36-2lo{{g}_{10}}3+lo{{g}_{10}}15\] \[=lo{{g}_{10}}{{36}^{1/2}}-lo{{g}_{10}}{{3}^{2}}+lo{{g}_{10}}15\] \[=lo{{g}_{10}}6-lo{{g}_{10}}9+lo{{g}_{10}}15\] \[={{\log }_{10}}\frac{6\times 15}{9}={{\log }_{10}}\frac{90}{9}={{\log }_{10}}10=1\]
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