A) \[-\left( 1+x \right)\]
B) \[{{\left( 1+x \right)}^{-1}}\]
C) \[\frac{a}{10}\]
D) \[\frac{1}{10a}\]
Correct Answer: A
Solution :
(a): \[{{\log }_{10}}\left( \frac{1}{80} \right)={{\log }_{10}}1-{{\log }_{10}}80\] \[=-~lo{{g}_{10}}(8\times 10)=(lo{{g}_{10}}8+lo{{g}_{10}}10)=-(x+1)\]
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