A) 1
B) \[\frac{3}{2}\]
C) 2
D) 3
Correct Answer: A
Solution :
(a): Given expression = \[\frac{1}{{{\log }_{x}}yz+{{\log }_{x}}x}+\frac{1}{{{\log }_{y}}zx+{{\log }_{y}}y}+\frac{1}{{{\log }_{z}}xz+{{\log }_{z}}z}\] \[=\frac{1}{{{\log }_{x}}(xyz)}+\frac{1}{{{\log }_{y}}(xyz)}+\frac{1}{{{\log }_{z}}(xyz)}=\] \[={{\log }_{xyz}}x+{{\log }_{xyz}}y+{{\log }_{xyz}}z\] \[={{\log }_{xyz}}(xyz)=1\].You need to login to perform this action.
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