A) \[\frac{5}{64}\]
B) 5
C) 16
D) 25
Correct Answer: D
Solution :
(d): \[\therefore {{16}^{{{\log }_{4}}5}}={{\left( {{4}^{2}} \right)}^{lo{{g}_{4}}5}}={{4}^{2lo{{g}_{1}}5}}={{4}^{lo{{g}_{4}}({{5}^{2}})}}\] \[={{4}^{{{\log }_{4}}25}}=25.\]
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