9th Class Mathematics Related to Competitive Exam Question Bank Logarithms

  • question_answer
    If \[log2=x,log3=y\] and log\[\mathbf{7}=\mathbf{z}\], then the value of \[\mathbf{log}\left( \mathbf{8}.\sqrt[3]{\mathbf{21}} \right)\]is:

    A)  \[2x+\frac{2}{3}y-\frac{1}{3}z\]          

    B)  \[2x+\frac{2}{3}y+\frac{1}{3}z\]

    C)  \[2x-\frac{2}{3}y+\frac{1}{3}z\]         

    D)  \[3x+\frac{1}{3}y+\frac{1}{3}z\]

    Correct Answer: D

    Solution :

    (d): \[log(8\sqrt[3]{21})=log8+log(\sqrt[3]{21})\] \[log8+log{{\left( 21 \right)}^{1/3}}=log\left( {{2}^{3}} \right)+log{{(7\times 3)}^{1/3}}\] \[=3\log 2+\frac{1}{3}\log 7+\frac{2}{3}\log 3=3x+\frac{1}{3}z+\frac{2}{3}y.\]


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