A) \[\frac{1}{2}\]
B) \[\frac{2}{3}\]
C) 1
D) \[\frac{1}{3}\]
Correct Answer: C
Solution :
(c): \[lo{{g}_{4}}3\times {{\log }_{27}}64=\frac{\log 3}{\log 4}\times \frac{\log 64}{\log 27}\] \[=\frac{\log 3}{\log 4}\times \frac{\log \left( {{4}^{3}} \right)}{\log \left( {{3}^{3}} \right)}=\frac{\log 3}{\log 4}\times \frac{3\log 4}{3\log 3}\]
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