A) \[\frac{1}{2}\]
B) \[\frac{2}{3}\]
C) 1
D) \[\frac{1}{3}\]
Correct Answer: C
Solution :
(c): \[{{\log }_{4}}3\times {{\log }_{27}}64=\frac{{{\log }_{3}}}{{{\log }_{4}}}\times \frac{\log 64}{\log 27}\] \[=\frac{\log \,3}{\log \,4}\times \frac{\log ({{4}^{3}})}{\log ({{3}^{3}})}=\frac{\log \,3}{\log \,4}\times \frac{3\log \,4}{3\log \,3}=1\]
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