question_answer

Expansion of \[\mathbf{log}{{\mathbf{~}}_{\mathbf{3}}}\left( \frac{\mathbf{27}{{\mathbf{x}}^{\mathbf{3}}}}{\mathbf{5}} \right)\] equals to E, then \[\frac{\mathbf{E}}{\mathbf{3}}\] is ________ 

A) \[1+{{\log }_{3}}x-\frac{1}{3}{{\log }_{3}}5\]

B)      \[3+3\text{ }{{\log }_{3}}x+{{\log }_{3}}5\]

C) \[1+\text{lo}{{\text{g}}_{3}}x+\text{lo}{{\text{g}}_{3}}5\]     

D)      \[{{\log }_{3}}x+\frac{1}{3}\text{lo}{{\text{g}}_{3}}5\]

E) None of these