A) \[\log x\]
B) \[\log (x-1)\]
C) x
D) None of these
Correct Answer: D
Solution :
\[{{e}^{\left( x\,-\,\frac{1}{2}{{(x\,-\,1)}^{2}}\,+\,\frac{1}{3}{{(x\,-\,1)}^{3}}-......... \right)}}\] \[={{e}^{\left( (x-1)-\frac{1}{2}{{(x-1)}^{2}}+\frac{1}{3}{{(x-1)}^{3}}-...... \right)\,\,+\,1}}\] = \[{{e}^{\log (1+x-1)}}e={{e}^{\log x}}.e=xe.\]
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