A) \[{{189}^{o}}\]
B) \[{{215}^{o}}\]
C) \[{{285}^{o}}\]
D) \[{{280}^{o}}\]
Correct Answer: C
Solution :
Draw \[EO||AB||CD\] So, \[\angle 1+\angle 2=x\] As \[EO||AB\]and OB is transversal \[\therefore \]\[\angle 1+\angle ABO={{180}^{o}}\](co-interior angles) \[\Rightarrow \]\[\angle 1+{{40}^{o}}={{180}^{o}}\Rightarrow \angle 1={{140}^{o}}\] Also, and DO is transversal \[\therefore \]\[\angle 2+\angle CDO={{180}^{o}}\](co-interior angles) \[\Rightarrow \]\[\angle 2+{{35}^{o}}={{180}^{o}}\Rightarrow \angle 2={{145}^{o}}\] \[\therefore \]\[\angle 1+\angle 2={{140}^{o}}+{{145}^{o}}={{285}^{o}}\] \[\therefore \]\[x={{285}^{o}}\] \[(\because \,x=\angle 1+\angle 2)\]You need to login to perform this action.
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