• # question_answer ) A and B are friends. A is elder to B by 5 years. B's sister C is half the age of B while A's father D is 8 years older than twice the age of B. If the present age of D is 48 years, find the present ages of A, B and C respectively. A)  50 years, 25 years, 20 yearsB)  40 years, 20 years, 15 yearsC)  20 years, 15 years, 10 yearsD)  25 years, 20 years, 10 years

Let the present ages of A, B, C and D are $x,y,z$and t respectively. Since, present age of D = t = 48 years. According to question, $x=y+5$                                             ?(i) $z=\frac{1}{2}y$                                                          ?(ii) $t=2y+8$                                            ?(iii) From (iii), $48=2y+8$ $\Rightarrow$   $2y=40\Rightarrow y=20$years From (ii), $x=\frac{1}{2}\times 20=10$years From (i), $x=20+5=25$years So, present ages of A, B and C are 25 year, 20, years and 10 years respectively.