A) 53
B) 45
C) 92
D) 63
Correct Answer: D
Solution :
Let units place digit be x. So tens place digit\[=9-x\]. \[\therefore \] The original number =10(9-x)+x = 90-10x + x=90 - 9x Now, after interchanging the digits, the number formed = 10 (x) + 9 - x = 9x + 9 \[\therefore \] According to question, we have 90 - 9x - 27 = 9x + 9 \[\Rightarrow -18x=-54\Rightarrow x=3\] So, the original number \[=90-9\times 3=63\]You need to login to perform this action.
You will be redirected in
3 sec