A) \[x=a,y=b\]
B) \[x={{a}^{2}},y={{b}^{2}}\]
C) \[x=3a,\text{ }y=b\]
D) \[x=a,y=2b\]
Correct Answer: B
Solution :
(b): \[\frac{x}{a}+\frac{y}{b}=a+b\] \[\frac{x}{{{a}^{2}}}+\frac{y}{{{b}^{2}}}=2\] Solving for x, y, we get\[x={{a}^{2}},\,\,y={{b}^{2}}\].You need to login to perform this action.
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