A) \[\frac{3}{2}\]
B) \[\frac{4}{7}\]
C) \[\frac{7}{3}\]
D) \[\frac{9}{2}\]
Correct Answer: A
Solution :
We have, \[x-\left( 2x-\frac{(5x-1)}{3} \right)=\frac{x-1}{3}+\frac{1}{2}\] \[\Rightarrow x-\left( \frac{6x-5x+1}{3} \right)=\frac{2x-2+3}{6}\] \[\Rightarrow \frac{3x-x-1}{3}=\frac{2x+1}{6}\] \[\Rightarrow 6(2x-1)=3(2x+1)\Rightarrow 12x-6=6x+3\] \[\Rightarrow 6x=9\Rightarrow x=\frac{9}{6}=\frac{3}{2}\]You need to login to perform this action.
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