A) 5
B) \[10\]
C) \[-14\]
D) \[12\]
Correct Answer: A
Solution :
We have, \[\frac{(3x+1)}{16}+\frac{(2x-3)}{7}=\frac{(x+3)}{8}+\frac{(3x-1)}{14}\] \[\Rightarrow \frac{7(3x+1)+16(2x-3)}{112}\] \[=\frac{14(x+3)+8(3x-1)}{112}\] \[\Rightarrow \frac{21x+7+32x-48}{112}=\frac{14x+42+24x-8}{112}\] \[\Rightarrow \frac{53x-41}{112}=\frac{38x+34}{112}\] \[\Rightarrow 53x-41=38x+34\Rightarrow 15x=75\] \[\Rightarrow x=\frac{75}{15}=5\]You need to login to perform this action.
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