A) (0.5, 1)
B) (6, 2)
C) (12, 5)
D) (8, 6)
Correct Answer: A
Solution :
(a): Put\[\frac{1}{2x+3y}={{t}_{1}}\] and\[\frac{1}{3x-2y}={{t}_{2}}\] \[\Rightarrow 12{{t}_{1}}+5{{t}_{2}}=-7\] and \[8{{t}_{1}}+6{{t}_{2}}=-10\Rightarrow 24{{t}_{1}}+10{{t}_{2}}=-14\] and \[24{{t}_{1}}+18{{t}_{2}}=-30\] \[\Rightarrow {{t}_{2}}=-2\] and \[{{t}_{1}}=\frac{1}{4}\Rightarrow 2x+3y=4\] and \[3x-2y=\frac{-1}{2}\]; Then solve to get \[x=0.5,y=1\]
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