A) \[30{}^\circ \]
B) \[45{}^\circ \]
C) \[60{}^\circ \]
D) zero
Correct Answer: D
Solution :
First we will calculate \[{{\delta }_{m}}\] for the given prism. \[\therefore \] \[\sqrt{2}=\frac{\sin (60+{{\delta }_{m}})/2}{\sin 30}\] \[\Rightarrow \] \[{{\delta }_{m}}\mathbf{=3}{{\mathbf{0}}^{\mathbf{o}}}\] It means that the given case is of minimum deviation. We know that in the position of minimum deviation, the refracted ray is parallel to the base of prism.
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