A) \[720m\times 720m\]
B) \[720m\times 720m\]
C) \[360cm\times 360cm\]
D) none of these
Correct Answer: A
Solution :
\[\frac{Area\,\,of\,\,the\,\,image}{Area\,\,of\,\,the\,\,object}=\]Aerial magnification\[={{m}^{2}}\]where \[m\] is the linear magnification \[\therefore \] \[m=\frac{f}{f+u}=\frac{0\cdot 5}{0\cdot 5}-2000\approx -\frac{1}{4000}\] Now, area of the image is equal to size of the camera film, therefore Area of object\[=\frac{Area\,\,of\,\,the\,\,image}{{{m}^{2}}}\] \[=18\times 18\times 4000\times 4000\] \[=72000\,\,cm\times 72000\,\,cm\] Note that \[m\] has no unit, so area of object is in same units as area of image.
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