A) 10 cm
B) 15 cm
C) 6.67cm
D) 11.67cm
Correct Answer: B
Solution :
Let \[{{x}_{1}}\] be the real distance of the bubble \[\therefore \] \[{{\mu }_{g}}=\frac{{{x}_{1}}}{6}\] \[\Rightarrow \] \[1.5=\frac{{{x}_{1}}}{6}\] \[{{x}_{1}}=1.56=9\,\,cm\] When viewed from other side,\[{{\mu }_{g}}=\frac{{{x}_{2}}}{4}\] \[\Rightarrow \] \[1.5=\frac{{{x}_{2}}}{4}\] \[\Rightarrow \] \[{{x}_{2}}=6\,\,cm=1.5\times 4\] \[\therefore \]Total thickness of slab\[={{x}_{1}}+{{x}_{2}}\] \[\mathbf{=9+6=15}\,\,\mathbf{cm}\]
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