A) 2/3
B) 3/2
C) 4/3
D) 9/4
Correct Answer: A
Solution :
\[{{V}_{a}}=3\times {{10}^{8}}m{{s}^{-1}}.....{{V}_{g}}=2\times {{10}^{8}}m{{s}^{-1}}\] \[_{a}{{\mu }^{g}}=\frac{{{V}_{g}}}{{{V}_{a}}}=\frac{2\times {{10}^{8}}}{3\times {{10}^{8}}}=\frac{2}{3}\]You need to login to perform this action.
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