A) \[\frac{\sin i}{\sin r}=\frac{\mu }{{{\mu }^{\text{l}}}}\]
B) \[\frac{\sin i}{\sin r}=\frac{{{\mu }^{\text{l}}}}{\mu }\]
C) \[\frac{\cos i}{\cos r}=\frac{{{\mu }^{\text{l}}}}{\mu }\]
D) \[\frac{sini}{sinr}=\frac{1}{\mu {{\mu }^{\text{l}}}}\]
Correct Answer: B
Solution :
\[{{\mu }_{1}}\sin i={{\mu }_{2}}\sin r;\] \[\mu \sin i={{\mu }^{|}}\sin r\]
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