A) \[{{H}_{2}}(g)+C{{l}_{2}}(g)=2HCl(g)\]
B) \[2CO(g)+{{O}_{2}}(g)=2C{{O}_{2}}(g)\]
C) \[{{N}_{2}}(g)+3{{H}_{2}}(g)=2N{{H}_{3}}(g)\]
D) \[PC{{l}_{5}}(g)\]⇌\[PC{{l}_{3}}(g)+C{{l}_{2}}(g)\]
Correct Answer: D
Solution :
Increase in volume, i.e., decrease in pressure shifts the equilibrium in the direction in which number of moles increases (Dn positive)
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