2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Equilibrium / साम्यावस्था

JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    Ammonia carbonate when heated to 200°C gives a mixture of \[N{{H}_{3}}\] and \[C{{O}_{2}}\]vapour with a density of 13.0. What is the degree of dissociation of ammonium carbonate [Kerala PMT 2004]

    A)                 \[3/2\] 

    B)                         \[1/2\]

    C)                 2             

    D)                 1

    E)                 \[5/2\]

    Correct Answer: D

    Solution :

               \[N{{H}_{2}}COON{{H}_{4}}\] ⇌ \[2N{{H}_{3}}+C{{O}_{2}}\]                     \[\alpha =\frac{D-d}{(n-1)\,d}\] where \[D\] is the density (initial)                    \[D=\frac{mol.\,wt}{2}=\frac{78}{2}=39\]                    \[n=\]no. of product = 3 \[d=\] final density                                 \[\alpha =\frac{39-13}{(3-1)\,13}=1\], so \[\alpha =1\]


You need to login to perform this action.
You will be redirected in 3 sec spinner