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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    What is the equilibrium expression for the reaction \[{{P}_{4(s)}}+5{{O}_{2(g)}}\]⇌ \[{{P}_{4}}{{O}_{10(s)}}\]                                                          [AIEEE 2004]

    A)                 \[{{K}_{c}}={{[{{O}_{2}}]}^{5}}\]               

    B)                         \[{{K}_{c}}=[{{P}_{4}}{{O}_{10}}]/5[{{P}_{4}}][{{O}_{2}}]\]

    C)                 \[{{K}_{c}}=[{{P}_{4}}{{O}_{10}}]/[{{P}_{4}}]{{[{{O}_{2}}]}^{5}}\]              

    D)                 \[{{K}_{c}}=1/{{[{{O}_{2}}]}^{5}}\]

    Correct Answer: D

    Solution :

               \[{{P}_{4}}(s)+5{{O}_{2}}(g)\] ⇌ \[{{P}_{4}}{{O}_{10}}(s)\]                    \[{{K}_{c}}=\frac{[{{P}_{4}}{{O}_{10}}(s)]}{[{{P}_{4}}(s)]{{[{{O}_{2}}(g)]}^{5}}}\]                                 We know that concentration of a solid component is always taken as unity \[{{K}_{c}}=\frac{1}{{{[{{O}_{2}}]}^{5}}}\]


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