2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Equilibrium / साम्यावस्था

JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    The reaction, \[2S{{O}_{2(g)}}+{{O}_{2(g)}}\]⇌ \[2S{{O}_{3(g)}}\] is carried out in a 1\[d{{m}^{3}}\]vessel and \[2\ d{{m}^{3}}\]vessel separately. The ratio of the reaction velocities will be                   [KCET 2004]

    A)                 \[1:8\]  

    B)                         \[1:4\]

    C)                 \[4:1\]  

    D)                 \[8:1\]

    Correct Answer: D

    Solution :

               \[2S{{O}_{2}}(g)+{{O}_{2}}(g)\]⇌\[2S{{O}_{3}}(g)\]                    For \[1d{{m}^{3}}\] \[R=k{{[S{{O}_{2}}]}^{2}}[{{O}_{2}}]\]                    \[R=K\ {{\left[ \frac{1}{T} \right]}^{2}}\left[ \frac{1}{1} \right]=1\]                    For \[2d{{m}^{3}}\] \[R=K\ {{\left[ \frac{1}{2} \right]}^{2}}\left[ \frac{1}{2} \right]=\frac{1}{8}\]                    So, the ratio is 8 : 1


You need to login to perform this action.
You will be redirected in 3 sec spinner