A) 2.5
B) 2.0
C) 0.5
D) 1.5
Correct Answer: B
Solution :
The rate of forward reaction is two times that of reverse reaction at a given temperature and identical concentration \[{{K}_{\text{equilibrium}}}\] is 2 because the reaction is reversible. So \[K=\frac{{{K}_{1}}}{{{K}_{2}}}=\frac{2}{1}=2\].
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