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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    4.5 moles each of hydrogen and iodine heated in a sealed ten litre vessel. At equilibrium, 3 moles of \[HI\] were found. The equilibrium constant for               \[{{H}_{2}}(g)+{{I}_{2}}(g)\]⇌\[2HI(g)\] is [EAMCET 1998]

    A)                 1             

    B)                 10

    C)                 5             

    D)                 0.33

    Correct Answer: A

    Solution :

                                  \[{{H}_{2}}\ +\ {{I}_{2}}\] ⇌  2HI                    Initial conc.    4.5   4.5        0                                           x      x         2x                     from question 2x = 3                                     \[x=\frac{3}{2}=1.5\]                    So conc. at eqm. \[4.5-1.5\] of \[{{H}_{2}}\]                    \[=4.5-1.5\] of \[{{I}_{2}}\] and 3 of HI                                 \[K=\frac{{{[HI]}^{2}}}{[{{I}_{2}}]\,\,[{{H}_{2}}]}=\frac{3\times 3}{3\times 3}=1\].


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