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JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    28 g  of \[{{N}_{2}}\] and 6 g  of \[{{H}_{2}}\] were kept at \[{{400}^{o}}C\] in 1 litre vessel, the equilibrium mixture contained  \[27.54g\] of \[N{{H}_{3}}\]. The approximate  value of \[{{K}_{c}}\] for the  above reaction can be (in \[mol{{e}^{-2}}\,\,litr{{e}^{2}}\])              [CBSE PMT 1990]

    A)                 75          

    B)                 50

    C)                 25          

    D)                 100

    Correct Answer: A

    Solution :

                \[{{N}_{2}}+3{{H}_{2}}\]⇌\[2N{{H}_{3}}\]                    Initial conc.         1          3           0                    at equilibrium 1-0.81    3-2.43   1.62                                           0.19       0.57                        No. of moles of \[{{N}_{2}}=\frac{28}{28}=1\]mole            No. of moles of \[{{H}_{2}}=\frac{6}{2}=3\]mole            No. of moles of \[N{{H}_{3}}=\frac{27.54}{17}=1.62\]mole                    \[{{K}_{c}}=\frac{{{[N{{H}_{3}}]}^{2}}}{[{{N}_{2}}]\,\,{{[{{H}_{2}}]}^{3}}}=\frac{{{[1.62]}^{2}}}{[0.19]\,\,{{[0.57]}^{3}}}\]=75


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