A) 3
B) 1
C) \[{{(1-\alpha )}^{2}}\]
D) \[(1+\alpha )\]
Correct Answer: D
Solution :
\[\underset{(1-\alpha )}{\mathop{\underset{1}{\mathop{{{N}_{2}}{{O}_{4}}}}\,}}\,\]⇌ \[\underset{2\,\alpha }{\mathop{\underset{0}{\mathop{2N{{O}_{2}}}}\,}}\,\] total mole at equilibrium \[=(1-\alpha )+2\alpha \]\[=1+\alpha \]
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