2. Questions Bank
  3. JEE Main & Advanced
  4. Chemistry
  5. Equilibrium / साम्यावस्था

JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    In the reversible reaction \[A+B\]⇌ \[C+D\], the concentration of each C and D at equilibrium was 0.8 mole/liter, then the equilibrium constant \[{{K}_{c}}\] will be               [MP PET 1986]

    A)                 6.4         

    B)                 0.64

    C)                 1.6         

    D)                 16.0

    Correct Answer: D

    Solution :

           Suppose 1 mole of A and B each taken then 0.8 mole/litre of C and D each formed remaining concentration of A and B will be (1 ? 0.8) = 0.2 mole/litre each.                                 \[Kc=\frac{[C]\,\,[D]}{[A]\,\,[B]}=\frac{0.8\times 0.8}{0.2\times 0.2}=16.0\]


You need to login to perform this action.
You will be redirected in 3 sec spinner