JEE Main & Advanced Chemistry Equilibrium / साम्यावस्था Question Bank Law of equilibrium and Equilibrium constant

  • question_answer
    For the system \[3A+2B\] ⇌ \[C\], the expression for equilibrium constant is [NCERT 1981; CPMT 1989; MP PMT 1990; RPMT 1999; Pb. PMT 2002; Pb. CET 2002]

    A)                 \[\frac{[3A][2B]}{C}\]    

    B)                 \[\frac{[C]}{[3A][2B]}\]

    C)                 \[\frac{{{[A]}^{3}}{{[B]}^{2}}}{[C]}\]       

    D)                 \[\frac{[C]}{{{[A]}^{3}}{{[B]}^{2}}}\]

    Correct Answer: D

    Solution :

           Equilibrium constant for the reaction , 3A + 2B ⇌ C is                                          K \[=\frac{[C]}{{{[A]}^{3}}{{[B]}^{2}}}\].


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